Question

How do you solve `sin theta= 1`?

Answer 1

`theta=pi/2+-n2pi` where n is a natural number

Explanation:

Let's look at a graph of `sintheta`:

graph{sinx [-6.25, 6.25, -2, 2]}

This is `sintheta` with `-2pi < theta < 2pi`

We can see that `sintheta=1` at `pi/2` and will repeat each cycle of the graph. And so the answer is:

`theta=pi/2+-n2pi` where n is a natural number