How do you solve #Sin (x) = cos (2x)# over the interval 0 to 2pi?
1 Answer
Mar 24, 2016
Explanation:
Since a - b + c = 0, use shortcut. The 2 real roots are: sin x = - 1 and
a. sin x = -1 -->
b.
Trig unit circle --> There are 2 arcs x that have same sin value
For interval