# How do you solve sin2x = √2 cosx, 0≤x≤ π?

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sin2x = #sqrt(2)# cosx, 0#<=# x#<=# #pi# ?

sin2x =

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Nghi N.
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Mar 24, 2017

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Use trig identity : sin 2x = 2sin x.cos x

Substitute in the equation sin 2x by 2sin x.cos x

Either one of the 2 factors should be zero:

a. cos x = 0 -->

b.

Trig unit circle gives 2 solutions:

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