Question

How do you solve `sinA-cosA=0`?

Answer 1

Solve (sin x - cos x) = 0.

Ans: `pi/4 and (5pi)/4`

Explanation:

Use trig identity:
`sin x - cos x = sqrt2sin (x - pi/4)`

`sin (x - pi/4) = 0`

a.`(x - pi/4) = 0` --> `x = pi/4`

b. `(x - pi/4) = pi`--> `x = pi + pi/4 = (5pi)/4`