Question

How do you solve `sinx-tanx=0`?

Answer 1

`x = kpi`
`x = 2kpi`

Explanation:

sin x - tan x = 0
`sin x - (sinx/cos x) = 0`
sin x.cos x - sin x = 0
sin x(cos x - 1) = 0
Either factor should be zero.
a. sin x = 0
Unit circle gives:
x = 0, `x = pi, and x = 2pi`
General answer: `x = kpi`
b. cos x - 1 = 0 --> cos x = 1
`x = 0 + 2kpi = 2kpi`