Question

How do you solve `sqrt(2) cos x + 1 = 0` from `[0,2pi]`?

Answer 1

Solve: `sqrt2cos x + 1 = 0`

Explanation:

`cos x = -(sqrt2)/2` --> `x = +- (3pi)/4`
Answer `x = (3pi)/4` and `x = (-3pi)/4 or (5pi)/4`