How do you solve sqrt(2x-6)<4√2x−6<4?

1 Answer
Jake L.
Sep 10, 2016

x = 11x=11

Explanation:

To begin,
sqrt(2x-6) < 4√2x−6<4

We can't do anything with that square root there, so let's get rid of it! We square both sides.
sqrt(2x-6)^2 < 4^2√2x−62<42
2x-6 < 162x−6<16

Now, we need to get rid of constants before coefficients, so we add 6 to both sides.
2x -6+6 < 16+62x−6+6<16+6
2x < 222x<22

Now, we can get rid of the 2!
We divide both sides by 2.
(2x)/2 < 22/22x2<222
x = 11 square

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