How do you solve #\sqrt { 4- x } - 5= 9#?

2 Answers
Nov 6, 2017

See a solution process below:

Explanation:

First, add #color(red)(5)# to each side of the equation to isolate the radical while keeping the equation balanced:

#sqrt(4 - x) - 5 + color(red)(5) = 9 + color(red)(5)#

#sqrt(4 - x) - 0 = 14#

#sqrt(4 - x) = 14#

Next, square both sides of the equation to eliminate the radical while keeping the equation balanced:

#(sqrt(4 - x))^2 = 14^2#

#4 - x = 196#

Then, subtract #color(red)(4)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(red)(4) + 4 - x = -color(red)(4) + 196#

#0 - x = 192#

#-x = 192#

Now, multiply each side of the equation by #color(red)(-1)# to solve for #x# while keeping the equation balanced:

#color(red)(-1) xx -x = color(red)(-1) xx 192#

#x = -192#

Nov 6, 2017

#x = -192#

Explanation:

#sqrt(4-x)=9+5#
Squaring both sides,
#4-x = 196#
#x= 4-196=-192#