# How do you solve  t(t + 4) - 1 = t(t + 2) + 2?

Aug 2, 2016

$t = \frac{3}{2}$

#### Explanation:

Distribute the brackets.

$\Rightarrow {t}^{2} + 4 t - 1 = {t}^{2} + 2 t + 2$

Collect 'like terms'
Terms in t to the left and numeric values to the right.

$\cancel{{t}^{2}} + 4 t - \cancel{{t}^{2}} - 2 t = 2 + 1$

Hence : 2t = 3

divide both sides by 2 to solve for t.

$\frac{{\cancel{2}}^{1} t}{\cancel{2}} ^ 1 = \frac{3}{2} \Rightarrow t = \frac{3}{2}$