Question

How do you solve `tan^2 (x) = 1/3` from `[0,2pi]`?

Answer 1

Solve `tan^2 x = 1/3` `(0, 2pi)`

Explanation:

`tan^2 x = 1/3.` --> `tan x = +- (sqrt3)/3`. Trig table gives -->

`x = pi/6 + kpi` and `x = (5pi)/6+ kpi`

Within the interval (0, 2pi), there are 4 answers:

`(pi)/6; and (pi/6 + pi) = (7pi)/6, (5pi)/6; and ((5pi)/6 + pi) = (11pi)/6`