To solve for #c#, get rid of the denominator, then move all the parts containing #c# to one side, then factor out #c#:
#tan55=(c+4)/c#
#tan55color(blue)(*c)=(c+4)/(c)color(blue)(*c)#
#tan55color(blue)(*c)=(c+4)/color(red)cancelcolor(black)(c)color(blue)(*color(red)cancelcolor(blue)c)#
#ctan55=c+4#
#ctan55-c=4#
#c(tan55-1)=4#
#color(blue)(color(black)(c(tan55-1))/(tan55-1))=color(blue)(color(black)4/(tan55-1))#
#color(blue)(color(black)(c color(red)cancelcolor(black)((tan55-1)))/color(red)cancelcolor(blue)(tan55-1))=color(blue)(color(black)4/(tan55-1))#
#c=color(blue)(color(black)4/(tan55-1))#
#color(white)c~~9.3425636...#
That's the solution. Hope this helped!