Question

How do you solve `tan(x/3) = 1` in the interval 0 to 2pi?

Answer 1

`x = (3pi)/4`

Explanation:

Trig table and unit circle -->
`tan (x/3) = 1 = tan (pi/4)`
2 solutions:
a. `x/3 = pi/4` --> `x = (3pi)/4`
b. `x/3 = (pi)/4 + pi = (5pi)/4 --> x = (15pi)/4` (rejected)
Answers for `(0, 2pi)`:
`x = (3pi)/4`