Question

How do you solve `tan(x)=cot(x)`?

Answer 1

First of all the conditions:

since there is the `y=tanx` function, `x!=pi/2+kpi`

since there is the `y=cotx` function, `x!=kpi`.

So, together: `x!=kpi/2`.

Than, remembering that `cotx=1/tanx`,

`tanx=1/tanxrArrtan^2x=1rArrtanx=+-1rArr`

`x=+-pi/4+kpi` both acceptable.