# How do you solve the compound inequalities 6b < 42 or 4b + 12 > 8?

May 22, 2015

$6 b < 42$
$\rightarrow b < 7$

$4 b + 12 > 8$
$\rightarrow 4 b > - 4$
$\rightarrow b > - 1$

Since all Real numbers are either $< 7$ or $> - 1$
the solution to the given compound inequalities is
all Real numbers