Question

How do you solve the compound inequalities `9 + 3n>=6` or `5n < 25`?

Answer 1

Handle each inequality separately and then recombine.

`9+3n>=6`
`rarr n>= -1`

`5n<25`
`rarr n<5`

So `9+3n>=6 " or " 5n<25`
is equivalent to
`n>=-1 " or " n<5`

But one or the other is true for any Real value of `n`
So
`n epsilon (-oo,+oo)`