How do you solve the compound inequality $2x+4>= -4$ and $2x-1<=3$ ?

Question

699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-02T08:51:30

$-4<=x<=2$

As $2x+4>=-4$ , we have

$2x>=-4-4$ or

$2x>=-8$ or $x>=-4$

Also we have $2x-1<=3$ i.e.

$2x<=3+1$ or

$2x<=4$ or $x<=2$

Now as we have $x>=-4$ as well as $x<=2$ ,

the solution can be summarized as

$-4<=x<=2$

How do you solve the compound inequality 2x+4>= -42x+4>= -4 and 2x-1<=32x-1<=3?