How do you solve the equation #2/3abs(5-2x)-1/2=5#?

Question

1306 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-26T10:33:37

Solution : #x= 6 5/8 , x = -1 5/8#

#2/3 |5-2x| -1/2 =5 or 2/3 |5-2x| = 5+1/2 # or

#2/3 |5-2x| =11/2 or |5-2x| = 3/2*11/2 # or

# |5-2x| =33/4 or 5 -2x = 33/4 or 2x =5-33/4 # or

#2x=-13/4 or x = -13/8 or x = -1 5/8# OR

# |5-2x| =33/4 or 5 -2x = -33/4 or 2x =5+33/4 # or

#2x= 53/4 or x = 53/8 or x = 6 5/8#

Solution : #x= 6 5/8 , x = -1 5/8# [Ans]