# How do you solve the equation: -32y^2-24y=0?

Jun 28, 2015

The solutions are:
color(blue)(y=0, y=-3/4

#### Explanation:

$- 32 {y}^{2} - 24 y = 0$

$- 8 y$ is common to both terms:

$= - 8 y \left(4 y + 3\right) = 0$

Equating the terms with zero to obtain the solution:

• $- 8 y = 0$
color(blue)(y=0

• $4 y + 3 = 0$
 color(blue)(y = -3/4