Question

How do you solve the equation `3x^2-5x-8=2x-3` by completing the square?

Answer 1

`x =1/6(7+-sqrt109)`

Explanation:

`3x^2 - 5x -8 =2x-3 or 3x^2 - 5x -8 -2x+3 =0` or

`3x^2 - 7x -5 =0 or 3 (x^2-7/3x) -5` or

`3(x^2-7/3x+(7/6)^2) - 3*49/36 -5 =0`

`3 (x-7/6)^2 - 49/12-5 or 3 (x-7/6)^2 = 109/12` or

`(x-7/6)^2 = 109/(3*12) or (x-7/6) = +- sqrt (109/36)` or

`x = 7/6+- sqrt (109)/6 =1/6(7+-sqrt109)` [Ans]