# How do you solve the equation abs(3x-3)=8?

Jul 11, 2017

${x}_{1} = \frac{11}{3}$
${x}_{2} = - \frac{5}{3}$

#### Explanation:

$\left\mid 3 x - 3 \right\mid = 8$

What is Absolute value/ modulus?
$\left(3 x - 3\right)$ might be positive or negative but we only need the positive value of it which is 8.

To solve the equation, and find $x$
we need to cancel off the modulus by adding $\pm$ sign to 8

$\left(3 x - 3\right) = \pm 8$
$3 x = \pm 8 + 3$
$x = \frac{\pm 8 + 3}{3}$

${x}_{1} = \frac{8 + 3}{3} = \frac{11}{3}$
${x}_{2} = \frac{- 8 + 3}{3} = - \frac{5}{3}$