# How do you solve the equation and identify any extraneous solutions for  x/(x-3) - 3/2 = 3/(x-3)?

Add $\frac{3}{2}$ to both sides to get:
$\frac{x}{x - 3} = \frac{3}{x - 3} + \frac{3}{2}$
Subtract $\frac{3}{x - 3}$ from both sides to get:
$\frac{3}{2} = \frac{x}{x - 3} - \frac{3}{x - 3} = \frac{x - 3}{x - 3} = 1$ with exclusion $x \ne 3$