# How do you solve the equation by graphing x^2 - 18x + 81 = 0?

If ${x}^{2} - 18 x + 81 = 0$, then it follows that ${\left(x - 9\right)}^{2} = 0$ through factorisation. Therefore $x$ can only equal $9$ for only that value satisfies the above equation.
To sketch this, you know that $\left(9 , 0\right)$ is your one and only $x$-intercept, and that your graph will turn at that coordinate too. Your $y$-intercept, reading from your original equation is at $\left(0 , 81\right)$.