How do you solve the equation for w: $(w + 1)^4 = 48$ ?

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Answer 1 · 2015-07-08T14:40:41

$w = -1+-2root(4)(3)$

Given $(w+1)^4 = 48$

$48 = 2^4(root(4)(3))^4 = (2root(4)(3))^4$

$(w+1)^4 = (2root(4)(3))^4$

$w+1 = +-2root(4)(3)$

$w=-1+-2root(4)(3)$

How do you solve the equation for w: (w + 1)^4 = 48(w + 1)^4 = 48?