# How do you solve the equation for w: (w + 1)^4 = 48?

Jul 8, 2015

$w = - 1 \pm 2 \sqrt[4]{3}$

#### Explanation:

Given ${\left(w + 1\right)}^{4} = 48$

$48 = {2}^{4} {\left(\sqrt[4]{3}\right)}^{4} = {\left(2 \sqrt[4]{3}\right)}^{4}$

${\left(w + 1\right)}^{4} = {\left(2 \sqrt[4]{3}\right)}^{4}$

$w + 1 = \pm 2 \sqrt[4]{3}$

$w = - 1 \pm 2 \sqrt[4]{3}$