Question

How do you solve the equation `log_10 16-log_10 (2t)=log_10 2`?

Answer 1

`t=4`

Explanation:

`log_(10)16-log_10(2t)=log_(10)2`

`log_(10)(16/(2t))=log_(10)2`

`=>16/(2t)=2`

`=>16=4t`

`=>t=4`