How do you solve the equation #x^2-3x-2=0# using the quadratic formula?
1 Answer
Oct 31, 2016
Explanation:
#x^2-3x-2=0#
is in the form:
#ax^2+bx+c = 0#
with
We can use the quadratic formula to find the roots:
#x = (-b+-sqrt(b^2-4ac))/(2a)#
#color(white)(x) = (-(color(blue)(-3))+-sqrt((color(blue)(-3))^2-4(color(blue)(1))(color(blue)(-2))))/(2(color(blue)(1)))#
#color(white)(x) = (3+-sqrt(9+8))/2#
#color(white)(x) = 3/2+-sqrt(17)/2#
