# How do you solve the exponential equation 7^x=7^(2x-3)?

Feb 17, 2017

$x = 3$

#### Explanation:

${7}^{x} = {7}^{2 x - 3}$

$x \log 7 = \left(2 x - 3\right) \log 7$

$x = 2 x - 3$

$x = 3$