How do you solve the following linear system #2x+3y= 3, 3x+y=3 #?

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Answer 1 · 2016-02-10T00:35:04

The easiest way in this situation would be substitution, and so I'll solve it that way for you.

To do substitution, you must isolate a variable.

#3x + y = 3#

#y = 3 - 3x#

#2x + 3(3 - 3x) = 3#

#2x + 9 - 9x = 3#

#-7x = -6#

#x = 6/7#

Plugging in #6/7# for x.

#3(6/7) + y = 3#

#y = 3 - 18/7#

#y = 3/7#

The solution set is #{6/7, 3/7}#

Hopefully this helps!