# How do you solve the following linear system: 3x-y=23 , y+8x=11 ?

Jul 7, 2017

See below.

#### Explanation:

Notice the coefficients of the $y$ term. It seems that adding is the simplest way to solve this.

$3 x - y = 23$
$+$
$8 x + y = 11$

$11 x = 34$

$x = \frac{34}{11}$

Plugging this in,

$3 \left(\frac{34}{11}\right) - y = 23$

$\frac{102}{11} - y = \frac{253}{11}$

$y = - \frac{151}{11}$

Thus, our solution is $\left(\frac{34}{11} , - \frac{151}{11}\right)$