How do you solve the following linear system: # 3y = 10 + 8x , x = 2y - 1 #?

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Answer 1 · 2016-03-13T15:54:58

Since one of the variables is already isolated, it's easiest to use substitution to solve.

#3y = 10 + 8x -> x = 2y - 1#

#3y = 10 + 8(2y - 1)#

#3y = 10 + 16y - 8#

#3y - 16y = 2#

#-13y = 2#

#y = -2/13#

#x = 2(-2/13) - 1#

#x = -4/13 - 1#

#x = -4/13 - 13/13#

#x = -17/13#

The solution set is #{-17/13, -2/13}#