How do you solve the following system:  3x + y = 2 , 4x + y = 2 ?

Jun 27, 2018

See a solution process below:

Explanation:

First, subtract the two equations:

$\textcolor{w h i t e}{-} 4 x + y = 2$
$- \left(3 x + y = 2\right)$
$\text{---------------------}$

$\textcolor{w h i t e}{-} 4 x + y = 2$
$- 3 x - y = - 2$
$\text{-----------------------}$
$1 x + 0 y = 0$

$1 x = 0$

$x = 0$

Now, substitute $0$ for $x$ in either equation and calculate $y$:

$3 x + y = 2$ becomes:

$\left(3 \times 0\right) + y = 2$

$0 + y 2$

$y = 2$

The Solution Is:

$x = 0$ and $y = 2$

Or

$\left(0 , 2\right)$