How do you solve the following system: 3x+y=2,4x+y=2?

1 Answer
Jun 27, 2018

See a solution process below:

Explanation:

First, subtract the two equations:

4x+y=2
(3x+y=2)
---------------------

4x+y=2
3xy=2
-----------------------
1x+0y=0

1x=0

x=0

Now, substitute 0 for x in either equation and calculate y:

3x+y=2 becomes:

(3×0)+y=2

0+y2

y=2

The Solution Is:

x=0 and y=2

Or

(0,2)