# How do you solve the following system: 4x+3y= -1 , 4x-2y=4 ?

Jan 11, 2016

$y = - 1$
$x = \frac{1}{2}$

#### Explanation:

Noting that the coefficient of $x$ is the same in both equations, we can get an expression just in $y$ buy subtracting the second equation from the first.
$4 x + 3 y = - 1$
$- \left(4 x - 2 y = 4\right)$
$5 y = - 5$
$y = - 1$
Substituting into either of the equations(I choose the second one) we can evaluate $x$
$4 x = 4 + 2 \cdot \left(- 1\right)$
$4 x = 2$
$x = \frac{1}{2}$