# How do you solve the following system: 4x-5y= -1, 4x+3y= -1 ?

Jan 14, 2016

I found:
$x = - \frac{1}{4}$
$y = 0$

#### Explanation:

I would try multiplying the first equation by $- 1$ and then add (in columns) to the second to get:
$\left\{\begin{matrix}\textcolor{red}{- 4 x - 5 y = 1} \\ 4 x + 3 x = - 1\end{matrix}\right.$ add them
$0 - 2 y = 0$
So:
$y = 0$
Substitute this back into the first equation:
$4 x - 0 = - 1$
$x = - \frac{1}{4}$