# How do you solve the following system?: 4x-y=-1 , 3x - 2y = 1

May 14, 2018

$x = - \frac{3}{5}$, $y = - \frac{7}{5}$

#### Explanation:

From the first equation, you have $y = 4 x + 1$. Substitute in the second equation to get

$3 x - 2 y = 1 \setminus \iff 3 x - 2 \left(4 x + 1\right) = 1 \setminus \iff 3 x - 8 x - 2 = 1$

So, you have $- 5 x = 3$ and thus $x = - \frac{3}{5}$

Since we knew that $y = 4 x + 1$, we have

$y = 4 \left(- \frac{3}{5}\right) + 1 = - \frac{12}{5} + 1 = - \frac{7}{5}$