# How do you solve the following system: -6x + y = -8, 6y + 4x = 12 ?

May 5, 2018

$y = 1$
$x = \frac{3}{2}$

#### Explanation:

$- 6 x + y = - 8$ --- (1)
$6 y + 4 x = 12$ --- (2)

From (1),
$- 6 x + y = - 8$
$y = 6 x - 8$ --- (3)

Sub (3) into (2)
$6 \left(6 x - 8\right) + 4 x = 12$
$36 x - 48 + 4 x = 12$
$40 x = 60$
$x = \frac{3}{2}$ --- (4)

Sub (4) into (3)
$y = 6 \cdot \frac{3}{2} - 8$
$y = 1$