How do you solve the following system: $7y - 2x = 10, 11y + 3x = 4$ ?

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Answer 1 · 2017-07-17T12:05:42

Arrange your equations, finding $x=-82/43$ and $y=38/43$

Enlarge the first equation with 3 and the second with 2:

$21y - 6x = 30$
$22y + 6x = 8$

Combine these equations:

$21y + 22y = 38$

$43y = 38$

$y=38/43$

Now you can find x, put this y value into any original equation

$21times(38/43) - 6x = 30$

$-6x = 30 - (798/43)$

$-6x = 492/43$

$x = -492/(43times6)$

$x= -82/43$

How do you solve the following system: 7y - 2x = 10, 11y + 3x = 4 7y - 2x = 10, 11y + 3x = 4 ?