# How do you solve the following system: x + 2y = 9 , 7x+15y=32 ?

The system is

$x + 2 y = 9$ (1)

$7 x + 15 y = 32$ (2)

Multiply the first equation by $- 7$ and add to the second you get

$\left(- 7\right) x - 14 y + 7 x + 15 y = - 63 + 32 \implies y = - 31$

hence $x = 9 + 2 \cdot 31 = 72$

The solution is $\left(x , y\right)$=$\left(72 , - 31\right)$