How do you solve the quadratic $10 x^{2} + 7 = - 3$ $10x^2+7=-3$ using any method?

Question

1585 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-29T16:48:37

Answer is $x = \pm i = \pm \sqrt{-} 1$ $x=+-i=+-sqrt-1$ .

$10 x^{2} + 7 = - 3$ $10x^2+7=-3$
$:.10x^2=-10$
$:.x^2=-1$
$:. x^2=i^2$ [ $i$ is imaginary number, $i=sqrt-1$ ]
$:.x=+-i$
$:.x=+-sqrt-1$ . (answer).

How do you solve the quadratic 10x^2+7=-310x2+7=−310x^2+7=-3 using any method?