# How do you solve the quadratic 3p^2-4=-6 using any method?

$p = \pm i \sqrt{\frac{2}{3}}$.
Add $4$ to both sides to get $3 {p}^{2} = - 2$.
Divide both sides by $3$ to get ${p}^{2} = - \frac{2}{3}$.
Square root both sides to get $p = \pm \sqrt{- \frac{2}{3}}$, which is equivalent to $p = \pm i \sqrt{\frac{2}{3}}$.