How do you solve the quadratic $9a^2+3=-27$ using any method?

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Answer 1 · 2016-09-07T18:04:26

There is no solution

first subtract by $3$

$9a^2=-30$

divide by $9$
$a^2=-30/9$

now take the square root but wait we can't do that for a negative so there is no solution.

You can try the quadratic formula but lets see what happens when we try that approach

$(-b +-sqrt(b^2 - 4ac))/(2a)$

$(0 +-sqrt(0 - 4*30))/(2) = sqrt(-120)/(2)$

Okay wait we see the same thing here, we cant really take the square root of a negative.

Lastly anytime you have an even exponent the answer will always be positive so this is rational enough to consider this an equation with no solution.

How do you solve the quadratic 9a^2+3=-279a^2+3=-27 using any method?