# How do you solve the quadratic equation #4x^2 - 8x + 1= 0# by using the Quadratic Formula?

##### 2 Answers

Using quadratic formula:

#### Explanation:

you assume the value

=> 4 to be your ''a''

=> -8 to be your ''b''

=> 1 to be your ''c''

Now just replace the values in the formula, and obtain your two values

-> N.B You will obtain two values (might be one positive one and the other, a negative one)

#### Explanation:

#color(blue)(4x^2-8x+1=0#

This is a Quadratic equation (in form

Use Quadratic equation

#color(brown)(x=(-b+-sqrt(b^2-4ac))/(2a)#

Note:

So,

#color(purple)(a=4,b=-8,c=1#

Remember that

Which implies that

#color(indigo)(x=((2+sqrt3)/(2),(2-sqrt3)/(2))#

If you are a bit confused with the Quadratic formula

Watch this video