# How do you solve the quadratic equation by completing the square: x^2+10x-2=0?

Aug 9, 2015

$x = - 5 \pm 3 \sqrt{3}$

#### Explanation:

Tranform the equation to this form
${x}^{2} + 10 - 2 = {\left(x + 5\right)}^{2} - 27 = 0$

Then rearrange to make $x$ the subject:
$x + 5 = \pm \sqrt{27} = \pm 3 \sqrt{3}$

=>

$x = - 5 \pm 3 \sqrt{3}$