How do you solve the rational equation #5/(y-2)=y+2#?
1 Answer
Mar 3, 2016
y = ± 3
Explanation:
To solve can
#color(blue)" cross multiply " # consider the equation as
#5/(y-2) = (y+2)/1 # now ' cross multiplying " gives
(y + 2 )(y - 2 ) = 5
distribute the brackets :
# y^2 - 4 = 5 rArr y^2 = 9 # so
# y^2 = 9 rArr y = sqrt9 = ± 3 #