How do you solve the rational equation #(x+2)/(x+1)-(x-4)/(x-3)=0#?

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Answer 1 · 2018-06-08T06:50:39

#x=1#

add #[x-4]/[x-3]# to both sides

#[x+2]/[x+1]=[x-4]/[x-3]#

multiply both sides by #(x+1)(x-3)#

#(x-3)(x+2)=(x-4)(x+1)#

#x^2+2x-3x-6=x^2+x-4x-4#

#x^2-x-6=x^2-3x-4#

add #x^2# to both sides

#-x-6=-3x-4#

add #3x# to both sides

#2x-6=-4#

add 6 to both sides

#2x=2#

divide by 2

#x=1#