# How do you solve the simultaneous equations 10x - 8y = 7 and 3x -2y = 2 ?

Jul 13, 2015

I found:
$x = \frac{1}{2}$
$y = - \frac{1}{4}$

#### Explanation:

I would nultiply the second equation by $- 4$ and get:
{10x-8y=7
{-12x+8y=-8 adding them:
$- 2 x + 0 = - 1$
so:
$x = \frac{1}{2}$
substituting back into the first equation you get:
$10 \cdot \frac{1}{2} - 8 y = 7$
$5 - 8 y = 7$
$- 8 y = 2$
$y = - \frac{1}{4}$