# How do you solve the simultaneous equations 2x+3y= -3 and 3x-2y=28?

Jul 29, 2015

I found:
$x = 6$
$y = - 5$

#### Explanation:

You could multiply the first equation by $2$ and the second by $3$ getting:
{4x+6y=-6
{9x-6y=84 add the two together (in columns):
$13 x + 0 = 78$
$x = \frac{78}{13} = 6$
substitute this value back into the first equation:
$2 \cdot 6 + 3 y = - 3$
$3 y = - 15$
$y = - \frac{15}{3} = - 5$