How do you solve the simultaneous equations 2x + 3y = 62x+3y=6 and 3x - 2y = 223x2y=22?

1 Answer
Jul 15, 2015

I found:
x=6x=6
y=-2y=2

Explanation:

You can start by multiplying the first equation by 33 and the second by -22 to get:
{6x+9y=18{6x+9y=18
{-6x+4y=-44{6x+4y=44
add the two equations (in columns) to get:
0+13y=-260+13y=26
So: y=-26/13=-2y=2613=2
Substitute back this value into the first equation:
2x+3(-2)=62x+3(2)=6
2x-6=62x6=6
2x=122x=12
x=12/2=6x=122=6