How do you solve the simultaneous equations #2x+3y=6 # and #3x-2y=22#?

1 Answer
Jul 23, 2015

Answer:

#{ (x=6), (y = -2) :}#

Explanation:

Simply multiply the first equation thoroughly by #2# and the second equation by #3# and subtract the results...

After the described multiplication, we get the result as

#4x + 6y = 12#
#9x - 6y = 66#
#stackrel("---------------------------")#

#13x = 78 implies x = 78/13 = 6#

Putting the value of #y# into the first equation, we have

#2 * 6 + 3y = 6#

#3y = 6 - 12#

#3y = -6 implies x = ((-6))/3 = -2#