How do you solve the simultaneous equations $2 x - 4 y = - 8$ $2x - 4y = -8$ and $2 x + 3 y = 17$ $2x +3y =17$ ?

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Answer 1 · 2015-07-23T17:04:44

$(x, y) \in {(\frac{22}{7}, \frac{25}{7})}$ $(x,y) in {(22/7, 25/7)}$

$x - 2 y = - 4$ $x - 2y = -4$

$x = 2 y - 4$ $x = 2y -4$

$2 (2 y - 4) + 3 y = 17$ $2(2y-4) + 3y = 17$

$4 y + 3 y = 17 + 8$ $4y + 3y = 17 + 8$

$y = \frac{25}{7}$ $y = 25/7$

$x = 2 \cdot \frac{25}{7} - 4$ $x = 2*25/7 - 4$

How do you solve the simultaneous equations 2x - 4y = -8 2x−4y=−82x - 4y = -8 and 2x +3y =172x+3y=172x +3y =17?