How do you solve the simultaneous equations 2x + 5y = 16 and 4x + 3y = 11 ?

Jul 13, 2015

I found:
$x = \frac{1}{2}$
$y = 3$

Explanation:

You can multiply the first equation by $- 2$ and add it to the second as:
{-4x-10y=-32
{4x+3y=11
add together the two equations in column (x with x, y with y, etc.):
$0 - 7 y = - 21$
so: $y = - \frac{21}{-} 7 = 3$ substitute this value back into the first equation to find $x$:
$2 x + 15 = 16$
$x = \frac{1}{2}$