# How do you solve the simultaneous equations 3x+y=1 and x-2y=19?

Jul 22, 2015

$\left(x , y\right) \setminus \in \left\{\left(3 , - 8\right)\right\}$

#### Explanation:

$y = 1 - 3 x$

$x - 2 \left(1 - 3 x\right) = 19$

$x - 2 + 6 x = 19$

$7 x = 21$

$x = 3$

$y = 1 - 3 \setminus \cdot 3$